Questions: Given points A(-2,4) and B(7,-2), find the coordinates of the point P on the directed line of AB that partitions AB in the ratio of 1:2.
Transcript text: 2) Given points $A(-2,4)$ and $B(7,-2)$, find the coordinates of the point $P$ on the directed line of $A B$ that partitions $A B$ in the ratio of $1: 2$.
Solution
Solution Steps
To find the coordinates of the point \( P \) that partitions the line segment \( AB \) in the ratio \( 1:2 \), we can use the section formula. The section formula for a point dividing a line segment in the ratio \( m:n \) is given by:
\[ P(x, y) = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right) \]
Here, \( A(x_1, y_1) = (-2, 4) \) and \( B(x_2, y_2) = (7, -2) \), and the ratio \( m:n = 1:2 \).
Step 1: Identify Points and Ratio
We are given points \( A(-2, 4) \) and \( B(7, -2) \) and need to find the coordinates of point \( P \) that divides the line segment \( AB \) in the ratio \( 1:2 \).
Step 2: Apply the Section Formula
Using the section formula, the coordinates of point \( P \) that divides the segment \( AB \) in the ratio \( m:n \) are given by:
\[
P(x, y) = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right)
\]
Substituting \( m = 1 \), \( n = 2 \), \( x_1 = -2 \), \( y_1 = 4 \), \( x_2 = 7 \), and \( y_2 = -2 \):
\[
P(x, y) = \left( \frac{1 \cdot 7 + 2 \cdot (-2)}{1+2}, \frac{1 \cdot (-2) + 2 \cdot 4}{1+2} \right)
\]
Step 3: Calculate Coordinates
Calculating the \( x \)-coordinate:
\[
P_x = \frac{7 - 4}{3} = \frac{3}{3} = 1.0
\]
Calculating the \( y \)-coordinate:
\[
P_y = \frac{-2 + 8}{3} = \frac{6}{3} = 2.0
\]
Final Answer
The coordinates of point \( P \) are \( (1.0, 2.0) \). Thus, we can express the final answer as:
\[
\boxed{P(1.0, 2.0)}
\]