Questions: Use the starting point and slope to graph the following equation: y=8/6 x+1

Use the starting point and slope to graph the following equation:
y=8/6 x+1
Transcript text: Use the starting point and slope to graph the following equation: \[ y=\frac{8}{6} x+1 \]
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Solution

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Solution Steps

Step 1: Identify the Slope and Y-Intercept

The given equation is \( y = \frac{8}{6}x + 1 \). This is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

  • Slope (\( m \)): \( \frac{8}{6} = \frac{4}{3} \)
  • Y-intercept (\( b \)): 1
Step 2: Determine the Starting Point

The starting point is the y-intercept, which is the point where the line crosses the y-axis. This point is \( (0, 1) \).

Step 3: Use the Slope to Find Another Point

From the starting point \( (0, 1) \), use the slope \( \frac{4}{3} \) to find another point on the line. The slope indicates that for every 3 units moved to the right (positive x-direction), the line moves up 4 units (positive y-direction).

  • Starting from \( (0, 1) \), move 3 units to the right to \( (3, 1) \).
  • Then move up 4 units to \( (3, 5) \).

Final Answer

The line passes through the points \( (0, 1) \) and \( (3, 5) \) with a slope of \( \frac{4}{3} \).

{"axisType": 3, "coordSystem": {"xmin": -5, "xmax": 5, "ymin": -5, "ymax": 5}, "commands": ["y = (4/3)x + 1"], "latex_expressions": ["$y = \\frac{8}{6}x + 1$"]}

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