Questions: 2(ln(2x)-ln(y))-(ln(3)+2ln(5))

2(ln(2x)-ln(y))-(ln(3)+2ln(5))
Transcript text: $2(\ln (2 x)-\ln (y))-(\ln (3)+2 \ln (5))$
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Solution

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Solution Steps

To simplify the given expression, we can use the properties of logarithms. Specifically, we can use the properties:

  1. ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right)
  2. aln(b)=ln(ba)a \ln(b) = \ln(b^a)
  3. ln(a)+ln(b)=ln(ab)\ln(a) + \ln(b) = \ln(ab)

Using these properties, we can simplify the expression step by step.

Solution Approach
  1. Apply the property ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) to the term inside the first set of parentheses.
  2. Apply the property aln(b)=ln(ba)a \ln(b) = \ln(b^a) to the term inside the second set of parentheses.
  3. Combine the results using the properties of logarithms.
Step 1: Rewrite the Expression

We start with the expression: 2(ln(2x)ln(y))(ln(3)+2ln(5)) 2(\ln(2x) - \ln(y)) - (\ln(3) + 2\ln(5))

Step 2: Apply Logarithmic Properties

Using the properties of logarithms, we can rewrite the expression: 2(ln(2x)ln(y))=2ln(2x)2ln(y)=ln((2x)2)ln(y2)=ln((2x)2y2) 2(\ln(2x) - \ln(y)) = 2\ln(2x) - 2\ln(y) = \ln((2x)^2) - \ln(y^2) = \ln\left(\frac{(2x)^2}{y^2}\right) And for the second part: (ln(3)+2ln(5))=ln(3)ln(52)=ln(3)ln(25)=ln(75) -(\ln(3) + 2\ln(5)) = -\ln(3) - \ln(5^2) = -\ln(3) - \ln(25) = -\ln(75)

Step 3: Combine the Results

Now we combine the two parts: ln((2x)2y2)ln(75)=ln((2x)275y2) \ln\left(\frac{(2x)^2}{y^2}\right) - \ln(75) = \ln\left(\frac{(2x)^2}{75y^2}\right)

Final Answer

Thus, the fully simplified expression is: ln(4x275y2) \boxed{\ln\left(\frac{4x^2}{75y^2}\right)}

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