We start with the equation: \[ 5v^{2} - 31v = 28 \] Rearranging it gives: \[ 5v^{2} - 31v - 28 = 0 \]
Next, we factor the polynomial \(5v^{2} - 31v - 28\). The factored form is: \[ (v - 7)(5v + 4) = 0 \]
To find the solutions, we set each factor equal to zero:
The solution set is: \[ \left\{ 7, -\frac{4}{5} \right\} \]
The solution set is \( \boxed{\left\{ 7, -\frac{4}{5} \right\}} \)
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