Questions: Use the spinner shown to answer the question. Assume that it is equally probable that the pointer will land on any one of the colored regions. If the pointer lands on a borderline, spin again. If the spinner is spun once, find the probability that the pointer lands in a region that is brown of red. The probability that the pointer lands in a region that is brown or red is (Type an integer or a simplified fraction.)

Use the spinner shown to answer the question. Assume that it is equally probable that the pointer will land on any one of the colored regions. If the pointer lands on a borderline, spin again.

If the spinner is spun once, find the probability that the pointer lands in a region that is brown of red.

The probability that the pointer lands in a region that is brown or red is 
(Type an integer or a simplified fraction.)
Transcript text: Use the spinner shown to answer the question. Assume that it is equally probable that the pointer will land on any one of the colored regions. If the pointer lands on a borderline, spin again. If the spinner is spun once, find the probability that the pointer lands in a region that is brown of red. The probability that the pointer lands in a region that is brown or red is $\square$ (Type an integer or a simplified fraction.)
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Solution

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Solution Steps

Step 1: Identify the total number of regions on the spinner

The spinner is divided into 8 equal regions.

Step 2: Count the number of favorable regions (brown or red)

There are 4 regions that are either brown or red:

  • 2 brown regions
  • 2 red regions
Step 3: Calculate the probability

The probability is the number of favorable regions divided by the total number of regions: \[ \text{Probability} = \frac{\text{Number of favorable regions}}{\text{Total number of regions}} = \frac{4}{8} = \frac{1}{2} \]

Final Answer

The probability that the pointer lands in a region that is brown or red is \(\frac{1}{2}\).

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