Questions: Find the derivative of f(w)=w (9/10)+5 w. What is the domain of f'(w) ?
Enclose numerators and denominators in parentheses. For example (a-b) /(1+n). Enter the domain in interval notation. For infinity, type infinity.
f'(w)=
Domain of f'(w)
Transcript text: Find the derivative of $f(w)=w \frac{9}{10}+5 w$. What is the domain of $f^{\prime}(w)$ ?
Enclose numerators and denominators in parentheses. For example $(a-b) /(1+n)$. Enter the domain in interval notation. For $\infty$, type infinity.
$f^{\prime}(w)=$
Domain of $f^{\prime}(w)$
Solution
Solution Steps
Step 1: Rewrite the function for clarity
The given function is:
\[
f(w) = w \cdot \frac{9}{10} + 5w.
\]
This can be rewritten as:
\[
f(w) = \frac{9}{10}w + 5w.
\]
Step 2: Combine like terms
Combine the terms involving \( w \):
\[
f(w) = \left( \frac{9}{10} + 5 \right) w.
\]
Simplify the coefficient:
\[
\frac{9}{10} + 5 = \frac{9}{10} + \frac{50}{10} = \frac{59}{10}.
\]
Thus, the function becomes:
\[
f(w) = \frac{59}{10}w.
\]
Step 3: Compute the derivative
The derivative of \( f(w) \) with respect to \( w \) is:
\[
f^{\prime}(w) = \frac{d}{dw} \left( \frac{59}{10}w \right).
\]
Since the derivative of \( w \) is 1, we have:
\[
f^{\prime}(w) = \frac{59}{10}.
\]
Step 4: Determine the domain of \( f^{\prime}(w) \)
The derivative \( f^{\prime}(w) = \frac{59}{10} \) is a constant function. The domain of a constant function is all real numbers. Therefore, the domain of \( f^{\prime}(w) \) is:
\[
(-\infty, \infty).
\]