Questions: Find the distance, d, of AB. A=(-3,4) B=(5,8) d=sqrt((x2-x1)^2+(y2-y1)^2) d=[?] Round to the nearest tenth.

Solution Steps

Substitute the coordinates of points A and B into the distance formula: $x_1 = -3$, $y_1 = 4$ $x_2 = 5$, $y_2 = 8$

$d = \sqrt{(5 - (-3))^2 + (8 - 4)^2}$

$d = \sqrt{(5+3)^2 + (4)^2}$ $d = \sqrt{8^2 + 4^2}$ $d = \sqrt{64 + 16}$ $d = \sqrt{80}$

$d \approx 8.944$ Rounding to the nearest tenth gives $d \approx 8.9$.

Final Answer