Questions: Figure 9: Instrumentation amplifier. Consider the circuit in Figure 9, which represents an instrumentation amplifier (A1, A2, A3) with additional functionality (A4, A5). All operational amplifiers are assumed to be ideal. (a) [5 points] Derive the transfer function H1(s) = (V2-V1)/(Vint-Vin). Hint: Set up independent equations that involve Ig, the current through Rg and eliminate Ig. Use your knowledge about ideal operational amplifiers. (b) [5 points] Derive an expression for (V01)/(Vout) of the sub-circuit with A 5 and for (V02)/(Vout) of the sub-circuit with A4. Calculate the transfer function H2(s) = (V02-V01)/(Vout). (c) [4 points] Set up the circuit equations for operational amplifier A3: Find a relationship between VN and VP, then set up circuit equations for V1, Vol, V2, and Vo 2 to derive the transfer function H3(s) = (V02-V0)/(V2-V1).

Figure 9: Instrumentation amplifier.
Consider the circuit in Figure 9, which represents an instrumentation amplifier (A1, A2, A3) with additional functionality (A4, A5). All operational amplifiers are assumed to be ideal.
(a) [5 points] Derive the transfer function H1(s) = (V2-V1)/(Vint-Vin). Hint: Set up independent equations that involve Ig, the current through Rg and eliminate Ig. Use your knowledge about ideal operational amplifiers.
(b) [5 points] Derive an expression for (V01)/(Vout) of the sub-circuit with A 5 and for (V02)/(Vout) of the sub-circuit with A4. Calculate the transfer function H2(s) = (V02-V01)/(Vout).
(c) [4 points] Set up the circuit equations for operational amplifier A3: Find a relationship between VN and VP, then set up circuit equations for V1, Vol, V2, and Vo 2 to derive the transfer function H3(s) = (V02-V0)/(V2-V1).
Transcript text: Figure 9: Instrumentation amplifier. Consider the circuit in Figure 9, which represents an instrumentation amplifier (A1, A2, A3) with additional functionality (A4, A5). All operational amplifiers are assumed to be ideal. (a) [5 points] Derive the transfer function $H_{1}(s)=\frac{V_{2}-V_{1}}{V_{\text {int }}-V_{\text {in }}}$. Hint: Set up independent equations that involve $I_{\mathrm{g}}$, the current through $R_{\mathrm{g}}$ and eliminate $I_{\mathrm{g}}$. Use your knowledge about ideal operational amplifiers. (b) [5 points] Derive an expression for $\frac{V_{01}}{V_{\text {out }}}$ of the sub-circuit with A 5 and for $\frac{V_{02}}{V_{\text {out }}}$ of the sub-circuit with A4. Calculate the transfer function $H_{2}(s)=\frac{V_{02}-V_{01}}{V_{\text {out }}}$. (c) [4 points] Set up the circuit equations for operational amplifier A3: Find a relationship between $V_{\mathrm{N}}$ and $V_{\mathrm{P}}$, then set up circuit equations for $V_{1}, V_{\mathrm{ol}}, V_{2}$, and $V_{\mathrm{o} 2}$ to derive the transfer function $H_{3}(s)=\frac{V_{02}-V_{0}}{V_{2}-V_{1}}$.
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Solution

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Step 1: Derive the transfer function H1(s)=V2V1Vin+Vin H_1(s) = \frac{V_2 - V_1}{V_{in+} - V_{in-}}
  1. Identify the voltages at the non-inverting inputs of A1 and A2:

    • Vin+ V_{in+} is at the non-inverting input of A1.
    • Vin V_{in-} is at the non-inverting input of A2.
  2. Assume ideal op-amps:

    • The voltage at the inverting input of A1 is V2 V_2 .
    • The voltage at the inverting input of A2 is V1 V_1 .
  3. Write the current equations:

    • The current through Rg R_g is Ig=V2V1Rg I_g = \frac{V_2 - V_1}{R_g} .
  4. Apply Kirchhoff's Current Law (KCL) at the inverting inputs of A1 and A2:

    • For A1: Vin+V2Rf=Ig \frac{V_{in+} - V_2}{R_f} = I_g
    • For A2: VinV1Rf=Ig \frac{V_{in-} - V_1}{R_f} = I_g
  5. Combine the equations:

    • Vin+V2Rf=V2V1Rg \frac{V_{in+} - V_2}{R_f} = \frac{V_2 - V_1}{R_g}
    • VinV1Rf=V2V1Rg \frac{V_{in-} - V_1}{R_f} = \frac{V_2 - V_1}{R_g}
  6. Solve for V2V1 V_2 - V_1 :

    • V2V1=(RgRf)(Vin+Vin) V_2 - V_1 = \left( \frac{R_g}{R_f} \right) (V_{in+} - V_{in-})
  7. Derive the transfer function H1(s) H_1(s) :

    • H1(s)=V2V1Vin+Vin=RgRf H_1(s) = \frac{V_2 - V_1}{V_{in+} - V_{in-}} = \frac{R_g}{R_f}
Step 2: Derive an expression for VO1Vout \frac{V_{O1}}{V_{out}} and VO2Vout \frac{V_{O2}}{V_{out}}
  1. Identify the sub-circuits:

    • VO1 V_{O1} is the output of A5.
    • VO2 V_{O2} is the output of A4.
  2. Assume ideal op-amps:

    • The voltage at the inverting input of A4 is VO2 V_{O2} .
    • The voltage at the inverting input of A5 is VO1 V_{O1} .
  3. Write the voltage divider equations:

    • For A4: Vout=VO2(1+R4R3) V_{out} = V_{O2} \left( 1 + \frac{R4}{R3} \right)
    • For A5: Vout=VO1(1+R5R2) V_{out} = V_{O1} \left( 1 + \frac{R5}{R2} \right)
  4. Solve for VO1Vout \frac{V_{O1}}{V_{out}} and VO2Vout \frac{V_{O2}}{V_{out}} :

    • VO1Vout=11+R5R2 \frac{V_{O1}}{V_{out}} = \frac{1}{1 + \frac{R5}{R2}}
    • VO2Vout=11+R4R3 \frac{V_{O2}}{V_{out}} = \frac{1}{1 + \frac{R4}{R3}}
  5. Derive the transfer function H2(s) H_2(s) :

    • H2(s)=VO2VO1Vout H_2(s) = \frac{V_{O2} - V_{O1}}{V_{out}}
Step 3: Set up the circuit equations for operational amplifier A3
  1. Identify the voltages at the inputs of A3:

    • VP V_P is at the non-inverting input of A3.
    • VN V_N is at the inverting input of A3.
  2. Assume ideal op-amps:

    • The voltage at the output of A3 is Vout V_{out} .
  3. Write the voltage equations:

    • VP=V2 V_P = V_2
    • VN=V1 V_N = V_1
  4. Combine the equations:

    • \( V_{out} = A3(V_P - V
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