When $\mathrm{BaCl}_{2}(\mathrm{aq})$ and $\mathrm{KIO}_{3}(\mathrm{aq})$ are mixed, the possible products are $\mathrm{Ba(IO}_{3})_{2}$ and $\mathrm{KCl}$. According to solubility rules, $\mathrm{Ba(IO}_{3})_{2}$ is insoluble in water and will precipitate out, while $\mathrm{KCl}$ is soluble.
\[
\mathrm{BaCl}_{2}(\mathrm{aq}) + 2\mathrm{KIO}_{3}(\mathrm{aq}) \rightarrow \mathrm{Ba(IO}_{3})_{2}(\mathrm{s}) + 2\mathrm{KCl}(\mathrm{aq})
\]
When $\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})$ and $\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq})$ are mixed, the possible products are $\mathrm{SrSO}_{4}$ and $\mathrm{NaNO}_{3}$. According to solubility rules, $\mathrm{SrSO}_{4}$ is insoluble in water and will precipitate out, while $\mathrm{NaNO}_{3}$ is soluble.
\[
\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq}) + \mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{SrSO}_{4}(\mathrm{s}) + 2\mathrm{NaNO}_{3}(\mathrm{aq})
\]
When $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})$ and $\mathrm{NaOH}(\mathrm{aq})$ are mixed, the possible products are $\mathrm{Pb(OH)}_{2}$ and $\mathrm{NaNO}_{3}$. According to solubility rules, $\mathrm{Pb(OH)}_{2}$ is insoluble in water and will precipitate out, while $\mathrm{NaNO}_{3}$ is soluble.
\[
\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq}) + 2\mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{Pb(OH)}_{2}(\mathrm{s}) + 2\mathrm{NaNO}_{3}(\mathrm{aq})
\]
- \(\mathrm{BaCl}_{2}(\mathrm{aq}) + 2\mathrm{KIO}_{3}(\mathrm{aq}) \rightarrow \mathrm{Ba(IO}_{3})_{2}(\mathrm{s}) + 2\mathrm{KCl}(\mathrm{aq})\)
- \(\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq}) + \mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{SrSO}_{4}(\mathrm{s}) + 2\mathrm{NaNO}_{3}(\mathrm{aq})\)
- \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq}) + 2\mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{Pb(OH)}_{2}(\mathrm{s}) + 2\mathrm{NaNO}_{3}(\mathrm{aq})\)