Questions: Use the quadratic formula to find the complex solutions of the quadratic equation. Give your answer(s) in a bi form. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) x=

Use the quadratic formula to find the complex solutions of the quadratic equation. Give your answer(s) in a bi form. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.)
x=
Transcript text: Use the quadratic formula to find the complex solutions of the quadratic equation. Give your answer(s) in a bi form. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) \[ x=\square \]
failed

Solution

failed
failed

Solution Steps

To find the complex solutions of a quadratic equation using the quadratic formula, follow these steps:

  1. Identify the coefficients aa, bb, and cc from the quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0.
  2. Use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
  3. Calculate the discriminant b24acb^2 - 4ac. If it is negative, the solutions will be complex.
  4. Compute the solutions using the formula, ensuring to handle the square root of a negative number to find the imaginary part.
Step 1: Identify Coefficients

The quadratic equation is given in the form ax2+bx+c=0 ax^2 + bx + c = 0 . For our case, we have:

  • a=1 a = 1
  • b=2 b = 2
  • c=3 c = 3
Step 2: Calculate the Discriminant

The discriminant D D is calculated using the formula: D=b24ac D = b^2 - 4ac Substituting the values: D=22413=412=8 D = 2^2 - 4 \cdot 1 \cdot 3 = 4 - 12 = -8

Step 3: Determine the Nature of the Roots

Since the discriminant D=8 D = -8 is negative, the quadratic equation has complex solutions.

Step 4: Apply the Quadratic Formula

The quadratic formula is given by: x=b±D2a x = \frac{-b \pm \sqrt{D}}{2a} Substituting the values: x=2±821 x = \frac{-2 \pm \sqrt{-8}}{2 \cdot 1} This simplifies to: x=2±2i22 x = \frac{-2 \pm 2i\sqrt{2}}{2} Thus, we can further simplify: x=1±i2 x = -1 \pm i\sqrt{2}

Final Answer

The complex solutions of the quadratic equation are: x=1+i2,1i2 \boxed{x = -1 + i\sqrt{2}, -1 - i\sqrt{2}}

Was this solution helpful?
failed
Unhelpful
failed
Helpful