Questions: 45-50 Find an expression for the function whose graph is the given curve. 45. The line segment joining the points (1,-3) and (5,7) 46. The line segment joining the points (-5,10) and (7,-10) 47. The bottom half of the parabola x+(y-1)^2=0

45-50 Find an expression for the function whose graph is the given curve.
45. The line segment joining the points (1,-3) and (5,7)
46. The line segment joining the points (-5,10) and (7,-10)
47. The bottom half of the parabola x+(y-1)^2=0
Transcript text: 45-50 Find an expression for the function whose graph is the given curve. 45. The line segment joining the points $(1,-3)$ and $(5,7)$ 46. The line segment joining the points $(-5,10)$ and $(7,-10)$ 47. The bottom half of the parabola $x+(y-1)^{2}=0$
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Solution

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Solution Steps

To find the expressions for the given functions, we need to determine the equations of the lines or curves described.

45. The line segment joining the points $(1,-3)$ and $(5,7)$

The equation of a line can be found using the two-point form of the line equation.

46. The line segment joining the points $(-5,10)$ and $(7,-10)$

Similarly, we use the two-point form of the line equation to find the equation of this line segment.

47. The bottom half of the parabola $x+(y-1)^{2}=0$

To find the expression for the bottom half of the parabola, we need to solve the given equation for \( y \) and consider only the negative square root to get the bottom half.

Step 1: Find the Equation of the Line Segment Joining \((1, -3)\) and \((5, 7)\)

To find the equation of the line passing through the points \((1, -3)\) and \((5, 7)\), we use the two-point form of the line equation:

\[ y = mx + b \]

where \( m \) is the slope and \( b \) is the y-intercept. The slope \( m \) is calculated as:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - (-3)}{5 - 1} = \frac{10}{4} = 2.5 \]

The y-intercept \( b \) is found using one of the points, say \((1, -3)\):

\[ -3 = 2.5 \cdot 1 + b \implies b = -3 - 2.5 = -5.5 \]

Thus, the equation of the line is:

\[ y = 2.5x - 5.5 \]

Step 2: Find the Equation of the Line Segment Joining \((-5, 10)\) and \((7, -10)\)

Similarly, for the points \((-5, 10)\) and \((7, -10)\), the slope \( m \) is:

\[ m = \frac{-10 - 10}{7 - (-5)} = \frac{-20}{12} = -1.6667 \]

Using the point \((-5, 10)\) to find the y-intercept \( b \):

\[ 10 = -1.6667 \cdot (-5) + b \implies b = 10 - 8.3333 = 1.6667 \]

Thus, the equation of the line is:

\[ y = -1.6667x + 1.6667 \]

Step 3: Find the Bottom Half of the Parabola \(x + (y-1)^2 = 0\)

To find the bottom half of the parabola given by the equation \(x + (y-1)^2 = 0\), we solve for \( y \):

\[ x + (y-1)^2 = 0 \implies (y-1)^2 = -x \implies y - 1 = \pm \sqrt{-x} \]

For the bottom half, we take the negative square root:

\[ y - 1 = -\sqrt{-x} \implies y = 1 - \sqrt{-x} \]

Final Answer

\[ \boxed{y = 2.5x - 5.5} \]

\[ \boxed{y = -\frac{5}{3}x + \frac{5}{3}} \]

\[ \boxed{y = 1 - \sqrt{-x}} \]

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