Questions: Next, the chemist measures the volume of the unknown liquid as 0.577 L and the mass of the unknown liquid as 728 g. Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. g . cm^-3 Given the data above, is it possible to identify the liquid? - yes - no - tetrahydrofuran - acetone - dimethyl sulfoxide - glycerol - pentane

Next, the chemist measures the volume of the unknown liquid as 0.577 L and the mass of the unknown liquid as 728 g.

Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. g . cm^-3

Given the data above, is it possible to identify the liquid? 
- yes 
- no 

- tetrahydrofuran 
- acetone 
- dimethyl sulfoxide 
- glycerol 
- pentane
Transcript text: Next, the chemist measures the volume of the unknown liquid as 0.577 L and the mass of the unknown liquid as 728 . g . \begin{tabular}{|l|l|} \hline \begin{tabular}{l} Calculate the density of the liquid. Be sure \\ your answer has the correct number of \\ significant digits. \end{tabular} & \begin{tabular}{l} $\mathrm{g} \cdot \mathrm{cm}^{-3}$ \end{tabular} \\ \hline \begin{tabular}{l} Given the data above, is it possible to \\ identify the liquid? \end{tabular} & \begin{tabular}{l} yes \\ no \end{tabular} \\ \hline & \begin{tabular}{l} tetrahydrofuran \\ acetone \\ dimethyl sulfoxide \\ glycerol \\ pentane \end{tabular} \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Calculate the Density of the Unknown Liquid

To calculate the density of the unknown liquid, we use the formula: $$\text{Density} = \frac{\text{Mass}}{\text{Volume}}$$ Given that the mass of the unknown liquid is 728 g and the volume is 577 cm^3, the calculated density is 1.262 g/cm^3 after rounding to 3 decimal places.

Step 2: Compare the Calculated Density with Known Densities

We compare the calculated density with the known densities of possible liquids. The calculated density closely matches the density of glycerol, with a difference of 0.001 g/cm^3.

Final Answer:

The unknown liquid is likely glycerol, based on its density.

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