The given equation is: \[ x^{\frac{10}{3}} = 27 \cdot x^{\frac{1}{3}} \]
To simplify, divide both sides by \( x^{\frac{1}{3}} \) (assuming \( x \neq 0 \)): \[ x^{\frac{10}{3}} \div x^{\frac{1}{3}} = 27 \]
Using the property of exponents \( x^a \div x^b = x^{a-b} \), we get: \[ x^{\frac{10}{3} - \frac{1}{3}} = 27 \] \[ x^{\frac{9}{3}} = 27 \] \[ x^3 = 27 \]
Take the cube root of both sides: \[ x = \sqrt[3]{27} \] \[ x = 3 \]
\[ \boxed{x = 3} \]
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