We start with the polynomial equation given by:
\[ 6r^{2} + 6r + 12 = 0 \]
The polynomial can be factorized as follows:
\[ 6 \left(r^{2} + r + 2\right) \]
To find the solutions for the equation, we solve:
\[ 6 \left(r^{2} + r + 2\right) = 0 \]
This leads us to the quadratic equation \( r^{2} + r + 2 = 0 \). The solutions to this equation are:
\[ r = -\frac{1}{2} - \frac{\sqrt{7}}{2}i \quad \text{and} \quad r = -\frac{1}{2} + \frac{\sqrt{7}}{2}i \]
The solutions to the polynomial equation are:
\[ \boxed{r = -\frac{1}{2} - \frac{\sqrt{7}}{2}i \quad \text{and} \quad r = -\frac{1}{2} + \frac{\sqrt{7}}{2}i} \]
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