The given reaction involves nickel(III) sulfite, Ni2(SO3)3\mathrm{Ni}_{2}\left(\mathrm{SO}_{3}\right)_{3}Ni2(SO3)3, and ammonium phosphate, (NH4)3PO4\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}(NH4)3PO4. These reactants are in aqueous form, as indicated by the (aq) state. The reaction is a precipitation reaction, which typically results in the formation of an insoluble solid (precipitate) and possibly other soluble products.
In a precipitation reaction, the cations and anions from the reactants exchange partners. The possible products are nickel(III) phosphate, NiPO4\mathrm{NiPO}_{4}NiPO4, and ammonium sulfite, (NH4)2SO3\mathrm{(NH}_{4})_{2}\mathrm{SO}_{3}(NH4)2SO3.
The unbalanced molecular equation for the reaction is: Ni2(SO3)3(aq)+(NH4)3PO4(aq)→NiPO4(s)+(NH4)2SO3(aq) \mathrm{Ni}_{2}\left(\mathrm{SO}_{3}\right)_{3}(aq) + \left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}(aq) \rightarrow \mathrm{NiPO}_{4}(s) + \mathrm{(NH}_{4})_{2}\mathrm{SO}_{3}(aq) Ni2(SO3)3(aq)+(NH4)3PO4(aq)→NiPO4(s)+(NH4)2SO3(aq)
To balance the equation, ensure that the number of each type of atom is the same on both sides of the equation.
The balanced equation is: Ni2(SO3)3(aq)+2(NH4)3PO4(aq)→2NiPO4(s)+3(NH4)2SO3(aq) \mathrm{Ni}_{2}\left(\mathrm{SO}_{3}\right)_{3}(aq) + 2\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}(aq) \rightarrow 2\mathrm{NiPO}_{4}(s) + 3\mathrm{(NH}_{4})_{2}\mathrm{SO}_{3}(aq) Ni2(SO3)3(aq)+2(NH4)3PO4(aq)→2NiPO4(s)+3(NH4)2SO3(aq)
The balanced molecular equation for the reaction is: Ni2(SO3)3(aq)+2(NH4)3PO4(aq)→2NiPO4(s)+3(NH4)2SO3(aq) \boxed{\mathrm{Ni}_{2}\left(\mathrm{SO}_{3}\right)_{3}(aq) + 2\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}(aq) \rightarrow 2\mathrm{NiPO}_{4}(s) + 3\mathrm{(NH}_{4})_{2}\mathrm{SO}_{3}(aq)} Ni2(SO3)3(aq)+2(NH4)3PO4(aq)→2NiPO4(s)+3(NH4)2SO3(aq)
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