Questions: The gram-formula mass of (NH4)2CO3 is (A) 96.0 g / mol (B) 78.0 g / mol (C) 64 g / mol (D) 46 g / mol

The gram-formula mass of (NH4)2CO3 is
(A) 96.0 g / mol
(B) 78.0 g / mol
(C) 64 g / mol
(D) 46 g / mol
Transcript text: The gram-formula mass of $\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}$ is (A) $96.0 \mathrm{~g} / \mathrm{mol}$ (B) $78.0 \mathrm{~g} / \mathrm{mol}$ (C) $64 \mathrm{~g} / \mathrm{mol}$ (D) $46 \mathrm{~g} / \mathrm{mol}^{\circ}$
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the Chemical Formula Components

The chemical formula for ammonium carbonate is \((\mathrm{NH}_4)_2\mathrm{CO}_3\). This compound consists of:

  • 2 ammonium ions \((\mathrm{NH}_4)^+\)
  • 1 carbonate ion \((\mathrm{CO}_3)^{2-}\)
Step 2: Calculate the Molar Mass of Each Component
  1. Ammonium Ion \((\mathrm{NH}_4)^+\):

    • Nitrogen (N): 1 atom × 14.01 g/mol = 14.01 g/mol
    • Hydrogen (H): 4 atoms × 1.008 g/mol = 4.032 g/mol
    • Total for one \((\mathrm{NH}_4)^+\): 14.01 + 4.032 = 18.042 g/mol
  2. Carbonate Ion \((\mathrm{CO}_3)^{2-}\):

    • Carbon (C): 1 atom × 12.01 g/mol = 12.01 g/mol
    • Oxygen (O): 3 atoms × 16.00 g/mol = 48.00 g/mol
    • Total for \((\mathrm{CO}_3)^{2-}\): 12.01 + 48.00 = 60.01 g/mol
Step 3: Calculate the Total Gram-Formula Mass
  • Total mass of 2 ammonium ions: \(2 \times 18.042 = 36.084\) g/mol
  • Total mass of 1 carbonate ion: \(60.01\) g/mol
  • Total gram-formula mass of \((\mathrm{NH}_4)_2\mathrm{CO}_3\): \[ 36.084 + 60.01 = 96.094 \, \text{g/mol} \]

Final Answer

The gram-formula mass of \((\mathrm{NH}_4)_2\mathrm{CO}_3\) is \(\boxed{96.0 \, \text{g/mol}}\).

Was this solution helpful?
failed
Unhelpful
failed
Helpful