Questions: Solve the equation by the method of your choice.
(3 x+3)(x+2)=2
The solution set is .
Transcript text: Solve the equation by the method of your choice.
\[
(3 x+3)(x+2)=2
\]
The solution set is $\square$ \}.
Solution
Solution Steps
To solve the equation \((3x + 3)(x + 2) = 2\), we can first expand the left-hand side to form a quadratic equation. Then, we can rearrange the equation to set it to zero and use the quadratic formula to find the values of \(x\).
Step 1: Expand the Equation
We start with the equation:
\[
(3x + 3)(x + 2) = 2
\]
Expanding the left-hand side gives:
\[
3x^2 + 6x + 3x + 6 = 2
\]
which simplifies to:
\[
3x^2 + 9x + 6 = 2
\]
Step 2: Rearrange the Equation
Next, we rearrange the equation to set it to zero:
\[
3x^2 + 9x + 6 - 2 = 0
\]
This simplifies to:
\[
3x^2 + 9x + 4 = 0
\]
Step 3: Apply the Quadratic Formula
We apply the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 3\), \(b = 9\), and \(c = 4\):
\[
x = \frac{-9 \pm \sqrt{9^2 - 4 \cdot 3 \cdot 4}}{2 \cdot 3}
\]
Calculating the discriminant:
\[
9^2 - 4 \cdot 3 \cdot 4 = 81 - 48 = 33
\]
Thus, the solutions are:
\[
x = \frac{-9 \pm \sqrt{33}}{6}
\]
This results in two solutions:
\[
x_1 = \frac{-9 - \sqrt{33}}{6}, \quad x_2 = \frac{-9 + \sqrt{33}}{6}
\]
Final Answer
The solution set is:
\[
\boxed{\left\{ \frac{-9 - \sqrt{33}}{6}, \frac{-9 + \sqrt{33}}{6} \right\}}
\]