To evaluate the quadratic function \( f(x) = -3x^2 - x - 15 \) at \( x = -8 \), substitute \(-8\) for \( x \) in the function and compute the result.
We start with the quadratic function given by
\[ f(x) = -3x^2 - x - 15 \]
To find \( f(-8) \), we substitute \(-8\) for \( x \):
\[ f(-8) = -3(-8)^2 - (-8) - 15 \]
Calculating the square of \(-8\):
\[ (-8)^2 = 64 \]
Now we substitute \( 64 \) back into the function:
\[ f(-8) = -3(64) + 8 - 15 \]
Calculating each term:
\[ -3(64) = -192 \]
Now, substituting this value into the equation:
\[ f(-8) = -192 + 8 - 15 \]
Now we combine the results:
\[ f(-8) = -192 + 8 = -184 \] \[ f(-8) = -184 - 15 = -199 \]
Thus, the value of \( f(-8) \) is
\[ \boxed{-199} \]
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