Questions: Question 1 14 pts Given tan(θ) = 5/6, then sin(θ) = a/b. Determine the values of a and b. a=[ Select ] b=[ Select ]

Question 1
14 pts

Given tan(θ) = 5/6, then sin(θ) = a/b.
Determine the values of a and b.
a=[ Select ]
b=[ Select ]
Transcript text: Question 1 14 pts Given $\tan (\theta)=\frac{5}{6}$, then $\sin (\theta)=\frac{a}{b}$. Determine the values of $a$ and $b$. \[ \begin{array}{l} a=[\text { Select }] \\ b=[\text { Select }] \end{array} \]
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Solution

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Solution Steps

Step 1: Understand the given information

We are given that \(\tan(\theta) = \frac{5}{6}\). Recall that \(\tan(\theta)\) is defined as the ratio of the opposite side to the adjacent side in a right triangle. Therefore, we can represent \(\theta\) as an angle in a right triangle where the opposite side is 5 units and the adjacent side is 6 units.

Step 2: Find the hypotenuse

Using the Pythagorean theorem, we can find the hypotenuse \(h\) of the right triangle: \[ h = \sqrt{5^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61}. \]

Step 3: Determine \(\sin(\theta)\)

The sine of an angle in a right triangle is defined as the ratio of the opposite side to the hypotenuse. Therefore: \[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{5}{\sqrt{61}}. \] To rationalize the denominator, multiply the numerator and denominator by \(\sqrt{61}\): \[ \sin(\theta) = \frac{5\sqrt{61}}{61}. \]

Final Answer

The values of \(a\) and \(b\) are: \[ a = 5\sqrt{61}, \quad b = 61. \] Thus, the final answer is: \[ \boxed{a = 5\sqrt{61}, \quad b = 61} \]

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