Questions: Question 1
14 pts
Given tan(θ) = 5/6, then sin(θ) = a/b.
Determine the values of a and b.
a=[ Select ]
b=[ Select ]
Transcript text: Question 1
14 pts
Given $\tan (\theta)=\frac{5}{6}$, then $\sin (\theta)=\frac{a}{b}$.
Determine the values of $a$ and $b$.
\[
\begin{array}{l}
a=[\text { Select }] \\
b=[\text { Select }]
\end{array}
\]
Solution
Solution Steps
Step 1: Understand the given information
We are given that \(\tan(\theta) = \frac{5}{6}\). Recall that \(\tan(\theta)\) is defined as the ratio of the opposite side to the adjacent side in a right triangle. Therefore, we can represent \(\theta\) as an angle in a right triangle where the opposite side is 5 units and the adjacent side is 6 units.
Step 2: Find the hypotenuse
Using the Pythagorean theorem, we can find the hypotenuse \(h\) of the right triangle:
\[
h = \sqrt{5^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61}.
\]
Step 3: Determine \(\sin(\theta)\)
The sine of an angle in a right triangle is defined as the ratio of the opposite side to the hypotenuse. Therefore:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{5}{\sqrt{61}}.
\]
To rationalize the denominator, multiply the numerator and denominator by \(\sqrt{61}\):
\[
\sin(\theta) = \frac{5\sqrt{61}}{61}.
\]
Final Answer
The values of \(a\) and \(b\) are:
\[
a = 5\sqrt{61}, \quad b = 61.
\]
Thus, the final answer is:
\[
\boxed{a = 5\sqrt{61}, \quad b = 61}
\]