To determine the element and the number of unpaired electrons, we need the electron configuration. However, since the configuration is not provided, let's assume a typical configuration format, such as:
\[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^x \]
Assuming the configuration ends with \(3p^x\), the element can be identified by counting the total number of electrons. For example, if \(x = 5\), the configuration would be:
\[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^5 \]
This totals 17 electrons, which corresponds to chlorine (Cl).
In the \(3p^5\) configuration, there are three \(p\) orbitals. The electron filling would be:
- One electron in each of the three orbitals (3 electrons)
- Two electrons paired in one orbital (2 electrons)
This results in one unpaired electron.
- The chemical symbol for Element \(E\) is \(\boxed{\text{Cl}}\).
- The number of unpaired electron spins is \(\boxed{1}\).