Questions: Find the horizontal intercepts of the function f(x)=3x-4-1 The intercepts are at x=
Transcript text: Find the horizontal intercepts of the function $f(x)=3|x-4|-1$ The intercepts are at $x=$ $\square$
Solution
Solution Steps
To find the horizontal intercepts (also known as x-intercepts) of the function \( f(x) = 3|x-4| - 1 \), we need to set the function equal to zero and solve for \( x \). This involves solving the equation \( 3|x-4| - 1 = 0 \) for \( x \).
Step 1: Understand the Problem
We need to find the horizontal intercepts (also known as x-intercepts) of the function \( f(x) = 3|x-4| - 1 \). The x-intercepts occur where the function equals zero, i.e., \( f(x) = 0 \).
Step 2: Set the Function Equal to Zero
Set the function equal to zero to find the x-intercepts:
\[
3|x-4| - 1 = 0
\]
Step 3: Solve for the Absolute Value
Add 1 to both sides of the equation:
\[
3|x-4| = 1
\]
Divide both sides by 3:
\[
|x-4| = \frac{1}{3}
\]
Step 4: Solve the Absolute Value Equation
The equation \( |x-4| = \frac{1}{3} \) implies two cases:
Case 1: \( x-4 = \frac{1}{3} \)
\[
x = 4 + \frac{1}{3} = \frac{12}{3} + \frac{1}{3} = \frac{13}{3}
\]
Case 2: \( x-4 = -\frac{1}{3} \)
\[
x = 4 - \frac{1}{3} = \frac{12}{3} - \frac{1}{3} = \frac{11}{3}
\]
Final Answer
The horizontal intercepts of the function are at:
\[
\boxed{x = \frac{13}{3}, \frac{11}{3}}
\]