The given resistors are \( R_1 = 10 \Omega \), \( R_2 = 12 \Omega \), \( R_3 = 5 \Omega \), and \( R_4 = 22 \Omega \). They are connected in series.
For resistors in series, the total resistance \( R_{total} \) is the sum of the individual resistances: \[ R_{total} = R_1 + R_2 + R_3 + R_4 \]
Substitute the given values: \[ R_{total} = 10 \Omega + 12 \Omega + 5 \Omega + 22 \Omega \] \[ R_{total} = 49 \Omega \]
The effective resistance of the combination is \( 49 \Omega \).
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