Questions: Consider the function f(x)=29(x-15)^2+7/9 Step 2 of 2: Find an equation for the axis of symmetry of the parabola defined by the given function. Write the exact answer. Do not round.

Solution Steps

To find the axis of symmetry for a parabola given by the function \( f(x) = a(x-h)^2 + k \), the axis of symmetry is the vertical line \( x = h \). In this case, the function is \( f(x) = 29(x-15)^2 + \frac{7}{9} \), so the axis of symmetry is \( x = 15 \).

The given function is \( f(x) = 29(x-15)^2 + \frac{7}{9} \). This is a quadratic function in vertex form, where \( a = 29 \), \( h = 15 \), and \( k = \frac{7}{9} \).

For a parabola defined by the function \( f(x) = a(x-h)^2 + k \), the axis of symmetry is given by the equation \( x = h \). In this case, since \( h = 15 \), the axis of symmetry is:

\[ x = 15 \]

Final Answer