Questions: For the given pair of equations, give the slopes of the lines, and then determine whether the two lines are parallel, perpendicular, or neither. 8 x-6 y=4 8 x+12 y=-1 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The slope of 8 x-6 y=4 is In. (Type an integer or a simplified fraction.) B. The slope of 8 x-6 y=4 is undefined.

For the given pair of equations, give the slopes of the lines, and then determine whether the two lines are parallel, perpendicular, or neither.

8 x-6 y=4
8 x+12 y=-1

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The slope of 8 x-6 y=4 is In.
(Type an integer or a simplified fraction.)
B. The slope of 8 x-6 y=4 is undefined.
Transcript text: For the given pair of equations, give the slopes of the lines, and then determine whether the two lines are parallel, perpendicular, or neither. \[ \begin{array}{l} 8 x-6 y=4 \\ 8 x+12 y=-1 \end{array} \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The slope of $8 x-6 y=4$ is $\square$ In. (Type an integer or a simplified fraction.) B. The slope of $8 x-6 y=4$ is undefined.
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Solution

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Solution Steps

Step 1: Find the Slopes

For the first equation \( 8x - 6y = 4 \), we rearrange it into slope-intercept form \( y = mx + b \):

\[ -6y = -8x + 4 \implies y = \frac{4}{6}x - \frac{4}{6} = \frac{2}{3}x - \frac{2}{3} \]

Thus, the slope \( m_1 \) is:

\[ m_1 = \frac{4}{6} = \frac{2}{3} \]

For the second equation \( 8x + 12y = -1 \), we also rearrange it:

\[ 12y = -8x - 1 \implies y = -\frac{8}{12}x - \frac{1}{12} = -\frac{2}{3}x - \frac{1}{12} \]

Thus, the slope \( m_2 \) is:

\[ m_2 = -\frac{2}{3} \]

Step 2: Determine the Relationship Between the Lines

To determine the relationship between the two lines, we compare their slopes:

  • The slopes are \( m_1 = \frac{2}{3} \) and \( m_2 = -\frac{2}{3} \).
  • Since \( m_1 \cdot m_2 = \frac{2}{3} \cdot -\frac{2}{3} = -\frac{4}{9} \), which is not equal to -1, the lines are neither parallel nor perpendicular.

Final Answer

The slope of \( 8x - 6y = 4 \) is \( \frac{2}{3} \) and the slope of \( 8x + 12y = -1 \) is \( -\frac{2}{3} \). The lines are neither parallel nor perpendicular.

Thus, the final answer is:

\[ \boxed{\text{The slope of } 8x - 6y = 4 \text{ is } \frac{2}{3} \text{ and the lines are neither parallel nor perpendicular.}} \]

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