Questions: The combustion of 4.00 grams of milk in a bomb calorimeter resulted in a temperature increase of 3.4°C. qcomb = -840 J What is the heat capacity of the calorimeter? Ccal = [?] J / °C Enter the magnitude. Do not round until the end. Use significant figures.

The combustion of 4.00 grams of milk in a bomb calorimeter resulted in a temperature increase of 3.4°C.
qcomb = -840 J

What is the heat capacity of the calorimeter?
Ccal = [?] J / °C

Enter the magnitude. Do not round until the end. Use significant figures.

Transcript text: The combustion of 4.00 grams of milk in a bomb calorimeter resulted in a temperature increase of $3.4^{\circ} \mathrm{C}$. \[ \mathrm{q}_{\text {comb }}=-840 \mathrm{~J} \] What is the heat capacity of the calorimeter? \[ \mathrm{C}_{\mathrm{cal}}=[?] \mathrm{J} /{ }^{\circ} \mathrm{C} \] Enter the magnitude. Do not round until the end. Use significant figures.

Solution

Solution Steps

Step 1: Understand the Problem

We need to find the heat capacity of the calorimeter, denoted as $ C_{\text{cal}} $, given the heat of combustion ($ q_{\text{comb}} $) and the temperature change ($ \Delta T $).

Step 2: Use the Formula for Heat Capacity

The formula to calculate the heat capacity of the calorimeter is:

\[ C_{\text{cal}} = \frac{q_{\text{comb}}}{\Delta T} \]

where: