Questions: Name(print) 1. Ultraviolet light is divided into three categories, UV-A, UV-B, and UV-C. The wavelength ranges (in nanometers) are shown in the Figure. Hint: 1 m = 10^9 nm. (a) Which type of UV-radiation is most energetic? UV-C (b) Calculate the energy (in Joules) of one photon of UV-A radiation (any wavelength in its range).

Name(print)
1. Ultraviolet light is divided into three categories, UV-A, UV-B, and UV-C. The wavelength ranges (in nanometers) are shown in the Figure. Hint: 1 m = 10^9 nm.
(a) Which type of UV-radiation is most energetic?
UV-C
(b) Calculate the energy (in Joules) of one photon of UV-A radiation (any wavelength in its range).
Transcript text: Name(print) 1. Ultraviolet light is divided into three categories, UV-A, UV-B, and UV-C. The wavelength ranges (in nanometers) are shown in the Figure. Hint: $1 \mathrm{~m}=\mathbf{1 0}^{9} \mathrm{~nm}$. (a) Which type of UV-radiation is most energetic? $V V-C$ (b) Calculate the energy (in Joules) of one photon of UV-A radiation (any wavelength in its range).
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Solution

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Solution Steps

Step 1: Identify the most energetic type of UV radiation
  • UV radiation is divided into three categories: UV-A, UV-B, and UV-C.
  • The energy of radiation is inversely proportional to its wavelength.
  • UV-C has the shortest wavelength range (200-280 nm), making it the most energetic.

Final Answer

  • The most energetic type of UV radiation is UV-C.
Step 2: Determine the wavelength range for UV-A
  • UV-A radiation has a wavelength range of 315-400 nm.
Step 3: Calculate the energy of one photon of UV-A radiation
  • Use the formula \( E = \frac{hc}{\lambda} \), where:

    • \( E \) is the energy of the photon,
    • \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) J·s),
    • \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s),
    • \( \lambda \) is the wavelength in meters.
  • Choose a wavelength within the UV-A range, for example, 350 nm (which is \( 350 \times 10^{-9} \) m).

Step 4: Perform the calculation
  • Substitute the values into the formula: \[ E = \frac{(6.626 \times 10^{-34} \text{ J·s}) (3.00 \times 10^8 \text{ m/s})}{350 \times 10^{-9} \text{ m}} \] \[ E = \frac{1.9878 \times 10^{-25} \text{ J·m}}{350 \times 10^{-9} \text{ m}} \] \[ E = 5.68 \times 10^{-19} \text{ J} \]
Final Answer
  • The energy of one photon of UV-A radiation (at 350 nm) is approximately 5.68 × 10⁻¹⁹ J.
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