Questions: Midterm Review Units 1-4 Question 5 The volume of a gas is 4.00 liters at 293 K and constant pressure. For the volume of the gas to become 3.00 liters, the Kelvin temperature must be equal to: A. 3.00×293 B. 293/3.00 C. 4.00×293 D. 3.00×4.00/293 E. 293/4.00×3.00 Submit Answer

Solution Steps

Use the ideal gas law relationship for constant pressure, which is given by Charles's Law: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Given:

• Initial volume, \( V_1 = 4.00 \) liters
• Initial temperature, \( T_1 = 293 \) K
• Final volume, \( V_2 = 3.00 \) liters

Rearrange Charles's Law to solve for the final temperature \( T_2 \): \[ T_2 = \frac{V_2 \cdot T_1}{V_1} \]

Substitute the known values into the equation: \[ T_2 = \frac{3.00 \, \text{liters} \times 293 \, \text{K}}{4.00 \, \text{liters}} \]

Perform the calculation: \[ T_2 = \frac{879}{4.00} \] \[ T_2 = 219.75 \, \text{K} \]

The correct option that matches this calculation is: \[ E. \frac{293}{4.00/3.00} \]

However, since the options provided do not directly match the simplified form, the closest correct option based on the calculation is: \[ E. \frac{293}{4.00/3.00} \]

Final Answer