Questions: A projectile is fired vertically, and its height (in feet) after t seconds is given by s(t)=-3 t^2+90 t+525. -Step 2 of 3: At what time will the projectile hit the ground? Round your final answer to the nearest hundredth. Answer seconds

A projectile is fired vertically, and its height (in feet) after t seconds is given by s(t)=-3 t^2+90 t+525.
-Step 2 of 3: At what time will the projectile hit the ground? Round your final answer to the nearest hundredth.

Answer
 seconds
Transcript text: A projectile is fired vertically, and its height (in feet) after $t$ seconds is given by $s(t)=-3 t^{2}+90 t+525$. -Step 2 of 3: At what time will the projectile hit the ground? Round your final answer to the nearest hundredth. AnswerHow to enter your answer (opens in new window) 2 Points $\square$ seconds
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Solution

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Solution Steps

Step 1: Set the Height Equation to Zero

To find when the projectile hits the ground, set the height equation \( s(t) = -3t^2 + 90t + 525 \) equal to zero, since the height at ground level is zero.

\[ -3t^2 + 90t + 525 = 0 \]

Step 2: Solve the Quadratic Equation

Use the quadratic formula to solve for \( t \). The quadratic formula is given by:

\[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]

For the equation \( -3t^2 + 90t + 525 = 0 \), identify the coefficients: \( a = -3 \), \( b = 90 \), and \( c = 525 \).

Step 3: Calculate the Discriminant

Calculate the discriminant \( b^2 - 4ac \):

\[ b^2 - 4ac = 90^2 - 4(-3)(525) \]

\[ = 8100 + 6300 \]

\[ = 14400 \]

Step 4: Apply the Quadratic Formula

Substitute the values into the quadratic formula:

\[ t = \frac{-90 \pm \sqrt{14400}}{2(-3)} \]

\[ t = \frac{-90 \pm 120}{-6} \]

Step 5: Calculate the Possible Values of \( t \)

Calculate the two possible values for \( t \):

  1. \( t = \frac{-90 + 120}{-6} = \frac{30}{-6} = -5 \) (not physically meaningful as time cannot be negative)
  2. \( t = \frac{-90 - 120}{-6} = \frac{-210}{-6} = 35 \)
Step 6: Round the Final Answer

Round the physically meaningful solution to the nearest hundredth:

\[ t = 35.00 \]

The projectile will hit the ground at \( 35.00 \) seconds.

Final Answer

\(\boxed{35.00}\) seconds

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