Questions: A projectile is fired vertically, and its height (in feet) after t seconds is given by s(t)=-3 t^2+90 t+525.
-Step 2 of 3: At what time will the projectile hit the ground? Round your final answer to the nearest hundredth.
Answer
seconds
Transcript text: A projectile is fired vertically, and its height (in feet) after $t$ seconds is given by $s(t)=-3 t^{2}+90 t+525$.
-Step 2 of 3: At what time will the projectile hit the ground? Round your final answer to the nearest hundredth.
AnswerHow to enter your answer (opens in new window) 2 Points
$\square$ seconds
Solution
Solution Steps
Step 1: Set the Height Equation to Zero
To find when the projectile hits the ground, set the height equation \( s(t) = -3t^2 + 90t + 525 \) equal to zero, since the height at ground level is zero.
\[ -3t^2 + 90t + 525 = 0 \]
Step 2: Solve the Quadratic Equation
Use the quadratic formula to solve for \( t \). The quadratic formula is given by:
\[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
For the equation \( -3t^2 + 90t + 525 = 0 \), identify the coefficients: \( a = -3 \), \( b = 90 \), and \( c = 525 \).
Step 3: Calculate the Discriminant
Calculate the discriminant \( b^2 - 4ac \):
\[ b^2 - 4ac = 90^2 - 4(-3)(525) \]
\[ = 8100 + 6300 \]
\[ = 14400 \]
Step 4: Apply the Quadratic Formula
Substitute the values into the quadratic formula:
\[ t = \frac{-90 \pm \sqrt{14400}}{2(-3)} \]
\[ t = \frac{-90 \pm 120}{-6} \]
Step 5: Calculate the Possible Values of \( t \)
Calculate the two possible values for \( t \):
\( t = \frac{-90 + 120}{-6} = \frac{30}{-6} = -5 \) (not physically meaningful as time cannot be negative)