Questions: Calculate the mass in grams of 1.13 mol of KMnO4. Be sure your answer has the correct number of significant figures. g KMnO4 × 10

Transcript text: Part 1 of 2 Calculate the mass in grams of 1.13 mol of $\mathrm{KMnO}_{4}$. Be sure your answer has the correct number of significant figures. $\square$ $\mathrm{g} \mathrm{KMnO}_{4}$ $\square$ $\square \times 10$

Solution

Solution Steps

Step 1: Determine the Molar Mass of KMnO$_4$

To find the mass of 1.13 mol of KMnO$_4$, we first need to calculate its molar mass. The molar mass is the sum of the atomic masses of all the atoms in the compound:

Potassium (K): 39.10 g/mol
Manganese (Mn): 54.94 g/mol
Oxygen (O): 16.00 g/mol (since there are 4 oxygen atoms, multiply by 4)

\[ \text{Molar mass of } \mathrm{KMnO}_4 = 39.10 + 54.94 + (4 \times 16.00) = 158.04 \, \text{g/mol} \]

Step 2: Calculate the Mass of 1.13 mol of KMnO$_4$

Now, use the molar mass to find the mass of 1.13 mol of KMnO$_4$:

\[ \text{Mass} = \text{moles} \times \text{molar mass} = 1.13 \, \text{mol} \times 158.04 \, \text{g/mol} \]

\[ \text{Mass} = 178.5852 \, \text{g} \]

Step 3: Round to the Correct Number of Significant Figures

The number of significant figures in the given moles (1.13) is three, so we round the calculated mass to three significant figures:

\[ \text{Mass} = 178.6 \, \text{g} \]