Questions: 10. What is an isotope? 11. What subatomic particles make up an atom? 12. Which subatomic particles make up atomic mass? 13. What is the average atomic mass of element X if, X - 123 has a relative abundance of 12%, X 127 has a relative abundance of 18%, and X-125 has a relative abundance of 70%?

10. What is an isotope?
11. What subatomic particles make up an atom?
12. Which subatomic particles make up atomic mass?
13. What is the average atomic mass of element X if, X - 123 has a relative abundance of 12%, X 127 has a relative abundance of 18%, and X-125 has a relative abundance of 70%?
Transcript text: 10. What is an isotope? 11. What subatomic particles make up an atom? 12. Which subatomic particles make up atomic mass? 13. What is the average atomic mass of element $X$ if, $X$ - 123 has a relative abundance of $12 \%, X$ 127 has a relative abundance of $18 \%$, and $X-125$ has a relative abundance of $70 \%$ ?
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Solution

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Solution Steps

Step 1: Define an Isotope

An isotope is a variant of a particular chemical element which differs in neutron number, and consequently in nucleon number. All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom.

\(\boxed{\text{An isotope is a variant of an element with the same number of protons but different numbers of neutrons.}}\)

Step 2: Identify Subatomic Particles in an Atom

An atom is made up of three types of subatomic particles:

  1. Protons (positively charged)
  2. Neutrons (neutral)
  3. Electrons (negatively charged)

\(\boxed{\text{Protons, Neutrons, and Electrons}}\)

Step 3: Determine Subatomic Particles Contributing to Atomic Mass

The atomic mass of an atom is primarily determined by the sum of the masses of protons and neutrons, as electrons have negligible mass.

\(\boxed{\text{Protons and Neutrons}}\)

Step 4: Calculate the Average Atomic Mass of Element \(X\)

To find the average atomic mass of element \(X\), we use the relative abundances and masses of its isotopes. The formula is:

\[ \text{Average Atomic Mass} = \sum (\text{isotope mass} \times \text{relative abundance}) \]

Given:

  • \(X-123\) with a relative abundance of \(12\%\)
  • \(X-127\) with a relative abundance of \(18\%\)
  • \(X-125\) with a relative abundance of \(70\%\)

Convert percentages to decimals:

  • \(12\% = 0.12\)
  • \(18\% = 0.18\)
  • \(70\% = 0.70\)

Calculate the average atomic mass: \[ \text{Average Atomic Mass} = (123 \times 0.12) + (127 \times 0.18) + (125 \times 0.70) \]

\[ = 14.76 + 22.86 + 87.50 \]

\[ = 125.12 \]

\(\boxed{125.1}\)

Final Answer

\(\boxed{\text{An isotope is a variant of an element with the same number of protons but different numbers of neutrons.}}\)

\(\boxed{\text{Protons, Neutrons, and Electrons}}\)

\(\boxed{\text{Protons and Neutrons}}\)

\(\boxed{125.1}\)

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