Questions: The Consumer Reports Restaurant Customer Satisfaction Survey is based upon 148,599 visits to full-service restaurant chains (Consume Reports website). One of the variables in the study is meal price, the average amount paid per person for dinner and drinks, minus the tip. Suppose a reporter for the Sun Coast Times thought that it would be of interest to her readers to conduct a similar study for restaurants located on the Grand Strand section in Myrtle Beach, South Carolina. The reporter selected a sample of 8 seafood restaurants, 8 Italian restaurants, and 8 steakhouses. The following data show the meal prices () obtained for the 24 restaurants sampled. Use α=0.05 to test whether there is a significant difference among the mean meal price for the three types of restaurants. Italian Seafood Steakhouse 10 15 22 12 17 18 15 15 23 16 25 25 18 25 19 22 15 24 15 21 28 26 17 32

The Consumer Reports Restaurant Customer Satisfaction Survey is based upon 148,599 visits to full-service restaurant chains (Consume Reports website). One of the variables in the study is meal price, the average amount paid per person for dinner and drinks, minus the tip. Suppose a reporter for the Sun Coast Times thought that it would be of interest to her readers to conduct a similar study for restaurants located on the Grand Strand section in Myrtle Beach, South Carolina. The reporter selected a sample of 8 seafood restaurants, 8 Italian restaurants, and 8 steakhouses. The following data show the meal prices () obtained for the 24 restaurants sampled. Use α=0.05 to test whether there is a significant difference among the mean meal price for the three types of restaurants.

Italian  Seafood  Steakhouse 
 10   15   22 
 12   17   18 
 15   15   23 
 16   25   25 
 18   25   19 
 22   15   24 
 15   21   28 
 26   17   32
Transcript text: The Consumer Reports Restaurant Customer Satisfaction Survey is based upon 148,599 visits to full-service restaurant chains (Consume Reports website). One of the variables in the study is meal price, the average amount paid per person for dinner and drinks, minus the tip. Suppose a reporter for the Sun Coast Times thought that it would be of interest to her readers to conduct a similar study for restaurants located on the Grand Strand section in Myrtle Beach, South Carolina. The reporter selected a sample of 8 seafood restaurants, 8 Italian restaurants, and 8 steakhouses. The following data show the meal prices $(\$)$ obtained for the 24 restaurants sampled. Use $\alpha=0.05$ to test whether there is a significant difference among the mean meal price for the three types of restaurants. \begin{tabular}{ccc} Italian & Seafood & Steakhouse \\ $\$ 10$ & $\$ 15$ & $\$ 22$ \\ $\$ 12$ & $\$ 17$ & $\$ 18$ \\ $\$ 15$ & $\$ 15$ & $\$ 23$ \\ $\$ 16$ & $\$ 25$ & $\$ 25$ \\ $\$ 18$ & $\$ 25$ & $\$ 19$ \\ $\$ 22$ & $\$ 15$ & $\$ 24$ \\ $\$ 15$ & $\$ 21$ & $\$ 28$ \\ $\$ 26$ & $\$ 17$ & $\$ 32$ \end{tabular}
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Solution

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Solution Steps

Step 1: Calculate the Sum of Squares

To perform the one-way ANOVA, we first calculate the sum of squares between groups and within groups.

The sum of squares between groups is given by: \[ SS_{between} = \sum_{i=1}^k n_i (\bar{X}_i - \bar{X})^2 = 216.0833 \]

The sum of squares within groups is calculated as: \[ SS_{within} = \sum_{i=1}^k \sum_{j=1}^{n_i} (X_{ij} - \bar{X}_i)^2 = 467.875 \]

Step 2: Calculate Mean Squares

Next, we compute the mean squares for both between and within groups.

The mean square between groups is: \[ MS_{between} = \frac{SS_{between}}{df_{between}} = \frac{216.0833}{2} = 108.0417 \]

The mean square within groups is: \[ MS_{within} = \frac{SS_{within}}{df_{within}} = \frac{467.875}{21} = 22.2798 \]

Step 3: Calculate the F-Statistic

The F-statistic is calculated using the mean squares: \[ F = \frac{MS_{between}}{MS_{within}} = \frac{108.0417}{22.2798} = 4.8493 \]

Step 4: Calculate the P-Value

The p-value is determined from the F-distribution: \[ P = 1 - F(F_{observed}; df_{between}, df_{within}) = 1 - F(4.8493; 2, 21) = 0.0186 \]

Step 5: Conclusion

With a significance level of \(\alpha = 0.05\), we compare the p-value to \(\alpha\):

  • Since \(P = 0.0186 < 0.05\), we reject the null hypothesis.

This indicates that there is a significant difference among the mean meal prices for the three types of restaurants.

Final Answer

\(\boxed{\text{Reject the null hypothesis: There is a significant difference among the mean meal prices for the three types of restaurants.}}\)

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