Questions: Mannitol, a carbohydrate, is supplied as a 25% (w/v) solution. This hypertonic solution is given to patients who have sustained a head injury with associated brain swelling. What volume should be given to provide a dose of 34 g ? Be sure your answer has the correct number of significant figures.
mL
100
Transcript text: Mannitol, a carbohydrate, is supplied as a $25 . \%\left(\frac{\mathrm{w}}{\mathrm{v}}\right)$ solution. This hypertonic solution is given to patients who have sustained a head injury with associated brain swelling. What volume should be given to provide a dose of $34 . \mathrm{g}$ ? Be sure your answer has the correct number of significant figures.
$\square$ mL
$\square$ 100
Solution
Solution Steps
Step 1: Understand the Problem
We need to determine the volume of a 25% (w/v) mannitol solution required to provide a dose of 34 grams of mannitol. The concentration of the solution is given as 25% (w/v), which means there are 25 grams of mannitol in every 100 mL of solution.
Step 2: Set Up the Equation
The concentration of the solution is given as 25% (w/v), which can be expressed as:
\[
\frac{25 \, \text{g}}{100 \, \text{mL}}
\]
We need to find the volume \( V \) in mL that contains 34 grams of mannitol. We can set up the equation:
\[
\frac{25 \, \text{g}}{100 \, \text{mL}} = \frac{34 \, \text{g}}{V \, \text{mL}}
\]
Step 3: Solve for the Volume
Cross-multiply to solve for \( V \):
\[
25 \times V = 34 \times 100
\]
\[
V = \frac{34 \times 100}{25}
\]
\[
V = \frac{3400}{25}
\]
\[
V = 136 \, \text{mL}
\]
Final Answer
The volume of the solution required to provide a dose of 34 grams of mannitol is \(\boxed{136 \, \text{mL}}\).