To find the intercepts of the equation \( y = -x^2 + 9 \), we need to determine where the graph intersects the x-axis and y-axis.
To find the y-intercept, we set \( x = 0 \) in the equation \( y = -x^2 + 9 \).
\[ y = -0^2 + 9 = 9 \]
Thus, the y-intercept is \( (0, 9) \).
To find the x-intercepts, we set \( y = 0 \) in the equation \( y = -x^2 + 9 \) and solve for \( x \).
\[ 0 = -x^2 + 9 \]
\[ x^2 = 9 \]
\[ x = \pm 3 \]
Thus, the x-intercepts are \( (3, 0) \) and \( (-3, 0) \).
\[ \boxed{(0, 9), (3, 0), (-3, 0)} \]
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