Questions: Bi-214 undergoes beta decay

Bi-214 undergoes beta decay
Transcript text: Bi-214 undergoes beta decay
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Solution

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Solution Steps

Step 1: Understanding Beta Decay

Beta decay is a type of radioactive decay in which a beta particle (an electron or a positron) is emitted from an atomic nucleus. In the case of beta-minus decay, a neutron in the nucleus is transformed into a proton, and an electron (beta particle) and an antineutrino are emitted.

Step 2: Identifying the Parent and Daughter Nuclei

Bi-214 (Bismuth-214) is the parent nucleus undergoing beta decay. During beta-minus decay, the atomic number of the nucleus increases by 1, while the mass number remains unchanged. Therefore, the daughter nucleus will have an atomic number of 84 (since Bismuth has an atomic number of 83) and a mass number of 214.

Step 3: Determining the Daughter Element

The element with atomic number 84 is Polonium (Po). Therefore, the daughter nucleus formed after the beta decay of Bi-214 is Po-214.

Final Answer

The beta decay of Bi-214 results in the formation of Po-214:

\[ \boxed{\text{Bi-214} \rightarrow \text{Po-214} + \beta^- + \bar{\nu}_e} \]

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