The given expression is:
\[ \frac{4}{x-2} + \frac{3}{5x-10} \]
First, notice that the denominator of the second fraction, \(5x - 10\), can be factored:
\[ 5x - 10 = 5(x - 2) \]
Thus, the expression becomes:
\[ \frac{4}{x-2} + \frac{3}{5(x-2)} \]
The common denominator for these fractions is \(5(x-2)\).
Rewrite the first fraction with the common denominator:
\[ \frac{4}{x-2} = \frac{4 \cdot 5}{(x-2) \cdot 5} = \frac{20}{5(x-2)} \]
The second fraction is already in terms of the common denominator:
\[ \frac{3}{5(x-2)} \]
Now that both fractions have the same denominator, add them:
\[ \frac{20}{5(x-2)} + \frac{3}{5(x-2)} = \frac{20 + 3}{5(x-2)} = \frac{23}{5(x-2)} \]
The simplified expression is:
\[ \boxed{\frac{23}{5(x-2)}} \]
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