The given quadratic function is in the standard form:
\[ f(x) = ax^2 + bx + c \]
For the function \( f(x) = x^2 + 8x + 12 \), we have:
To convert the quadratic function into vertex form, we need to complete the square. The vertex form of a quadratic function is:
\[ f(x) = a(x - h)^2 + k \]
First, focus on the quadratic and linear terms: \( x^2 + 8x \).
To complete the square, take half of the coefficient of \( x \), square it, and add and subtract it inside the function:
Add and subtract 16 inside the function:
\[ f(x) = (x^2 + 8x + 16) - 16 + 12 \]
Now, simplify the expression:
\[ f(x) = (x + 4)^2 - 4 \]
This is the vertex form of the quadratic function.
The function in vertex form is:
\[ \boxed{f(x) = (x + 4)^2 - 4} \]
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