Questions: Inhibiting the Action of Catechol Oxidase- Mixing Table and Results ENZYME Inhibitor SUBSTRATE Absorbance 540 nm ------------------ Tube Catechol oxidase DI Water PTU 1% catechol 1 1 mL 2 ml 2 1 ml 1 ml ... 3 1 ml 1 ml 1 ml 1 ml 1.945 4 1 ml ... 1 ml 2 ml 0.158 Tubes were prepared according to the above mixing table and the absorbance at 540 nm recorded. The question being investigated is: "What type of inhibitor is PTU, competitive or noncompetitive?" The hypothesis tested is that PTU is a competitive inhibitor. 1. Explain the experimental design. What is the purpose of test tubes 1,2,3 and 4? 2. Does the data support the hypothesis? Explain your results in terms of the data.

Inhibiting the Action of Catechol Oxidase-

Mixing Table and Results

  ENZYME   Inhibitor  SUBSTRATE  Absorbance 540 nm 
------------------
 Tube  Catechol oxidase  DI Water  PTU  1% catechol  
 1  1 mL  2 ml    
 2  1 ml  1 ml   ...  
 3  1 ml  1 ml  1 ml  1 ml  1.945 
 4  1 ml  ...  1 ml  2 ml  0.158 

Tubes were prepared according to the above mixing table and the absorbance at 540 nm recorded. The question being investigated is: "What type of inhibitor is PTU, competitive or noncompetitive?" The hypothesis tested is that PTU is a competitive inhibitor.

1. Explain the experimental design. What is the purpose of test tubes 1,2,3 and 4?
2. Does the data support the hypothesis? Explain your results in terms of the data.
Transcript text: 4.2 Inhibiting the Action of Catechol Oxidase- Mixing Table and Results \begin{tabular}{|l|c|c|c|c|c|} \hline & ENZYME & & Inhibitor & SUBSTRATE & \begin{tabular}{l} Absorbance \\ 540 nm \end{tabular} \\ \hline Tube & Catechol oxidase & DI Water & PTU & $1 \%$ catechol & \\ \hline 1 & 1 mL & 2 ml & & & \\ \hline 2 & 1 ml & 1 ml & & $\ldots$ & \\ \hline 3 & 1 ml & 1 ml & 1 ml & 1 ml & 1.945 \\ \hline 4 & 1 ml & $\ldots$ & 1 ml & 2 ml & 0.158 \\ \hline \end{tabular} Tubes were prepared according to the above mixing table and the absorbance $@ 540$ nm recorded. The question being investigated is: "What type of inhibitor is PTU, competitive or noncompetitive?" The hypothesis tested is that PTU is a competitive inhibitor. 1. Explain the experimental design. What is the purpose of test tubes $1,2,3$ and 4 ? 2. Does the data support the hypothesis? Explain your results in terms of the data. Edit View Insert Format Tools Table $14 \mathrm{px} \sim$ Paragraph $\vee \quad B \quad I \underline{U}$
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Solution

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  1. Explanation of the Experimental Design:

    • Purpose of Test Tubes:
      • Tube 1: This tube contains catechol oxidase and DI water. It serves as a control to observe the baseline activity of the enzyme without any substrate or inhibitor. This helps in understanding the natural absorbance level without any reaction.
      • Tube 2: This tube contains catechol oxidase, DI water, and a substrate (catechol). It serves as a positive control to show the enzyme activity in the presence of the substrate, allowing for the measurement of the enzyme's activity without any inhibitor.
      • Tube 3: This tube contains catechol oxidase, DI water, PTU (the inhibitor), and catechol (the substrate). It is used to observe the effect of PTU on the enzyme activity when both the substrate and inhibitor are present. The absorbance value here indicates the level of inhibition.
      • Tube 4: This tube contains catechol oxidase, PTU, and a higher concentration of catechol. It is used to determine if increasing the substrate concentration can overcome the inhibition by PTU, which is a characteristic of competitive inhibition.
  2. Does the Data Support the Hypothesis?

    • Analysis of Results:

      • Tube 3: The absorbance is 1.945, indicating that the enzyme activity is significantly inhibited by PTU when both the inhibitor and substrate are present.
      • Tube 4: The absorbance is 0.158, which is much lower than in Tube 3. This suggests that increasing the substrate concentration does not overcome the inhibition by PTU.
    • Conclusion:

      • The data does not support the hypothesis that PTU is a competitive inhibitor. In competitive inhibition, increasing the substrate concentration should reduce the effect of the inhibitor, leading to higher absorbance in Tube 4 compared to Tube 3. However, the absorbance in Tube 4 is much lower, suggesting that PTU is likely a noncompetitive inhibitor, as the inhibition is not overcome by increasing substrate concentration.
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