Questions: Identifying the center and radius to graph a circle given its equation in..
The equation of a circle is given below. Identify the radius and the center. Then graph the circle.
2 x^2 + 2 y^2 - 4 x + 12 y - 30 = 0
Radius: 5
Center: (1,-3)
Transcript text: Identifying the center and radius to graph a circle given its equation in..
The equation of a circle is given below. Identify the radius and the center. Then graph the circle.
\[
2 x^{2}+2 y^{2}-4 x+12 y-30=0
\]
Radius: 5
Center: $(1,-3)$
Solution
Solution Steps
Step 1: Rewrite the given equation in standard form
The given equation is:
\[ 2x^2 + 2y^2 - 4x + 12y - 30 = 0 \]
First, divide the entire equation by 2 to simplify:
\[ x^2 + y^2 - 2x + 6y - 15 = 0 \]
Step 2: Complete the square for the x and y terms
Group the x and y terms:
\[ (x^2 - 2x) + (y^2 + 6y) = 15 \]
Complete the square for \(x\):
\[ x^2 - 2x \rightarrow (x - 1)^2 - 1 \]
Complete the square for \(y\):
\[ y^2 + 6y \rightarrow (y + 3)^2 - 9 \]
Step 3: Rewrite the equation in standard form
Substitute the completed squares back into the equation:
\[ (x - 1)^2 - 1 + (y + 3)^2 - 9 = 15 \]
Combine constants on the right side:
\[ (x - 1)^2 + (y + 3)^2 - 10 = 15 \]
\[ (x - 1)^2 + (y + 3)^2 = 25 \]
Final Answer
The standard form of the circle's equation is:
\[ (x - 1)^2 + (y + 3)^2 = 25 \]