Questions: Identify the slope and y-intercept for the linear equation below.
y=-1/2 x-2
Transcript text: Identify the slope and $y$-intercept for the linear equation below.
\[
y=-\frac{1}{2} x-2
\]
Solution
Solution Steps
To identify the slope and \( y \)-intercept of a linear equation in the form \( y = mx + b \), we need to recognize that \( m \) represents the slope and \( b \) represents the \( y \)-intercept. For the given equation \( y = -\frac{1}{2}x - 2 \), we can directly read off these values.
Step 1: Identify the Form of the Equation
The given equation is \( y = -\frac{1}{2}x - 2 \). This is in the slope-intercept form, \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept.
Step 2: Determine the Slope
From the equation \( y = -\frac{1}{2}x - 2 \), the coefficient of \( x \) is the slope. Therefore, the slope \( m \) is \( -\frac{1}{2} \).
Step 3: Determine the \( y \)-Intercept
The constant term in the equation \( y = -\frac{1}{2}x - 2 \) is the \( y \)-intercept. Therefore, the \( y \)-intercept \( b \) is \( -2 \).
Final Answer
The slope is \( \boxed{-\frac{1}{2}} \) and the \( y \)-intercept is \( \boxed{-2} \).