Questions: Find two different points on the graph of the equation (y=-frac73 x+10) ((square square square ),( square square )

Find two different points on the graph of the equation (y=-frac73 x+10) ((square square square ),( square square )
Transcript text: Find two different points on the graph of the equation $y=-\frac{7}{3} x+10$ $(\square$ $\square$ $\square$ ),( $\square$ $\square$ )
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Solution

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Solution Steps

To find two different points on the graph of the equation \( y = -\frac{7}{3}x + 10 \), we can choose two different values for \( x \) and calculate the corresponding \( y \) values using the equation. This will give us two points in the form \((x, y)\).

Step 1: Choose Values for \( x \)

To find two points on the graph of the equation \( y = -\frac{7}{3}x + 10 \), we start by selecting two different values for \( x \). Let's choose \( x_1 = 0 \) and \( x_2 = 3 \).

Step 2: Calculate Corresponding \( y \) Values

Using the equation \( y = -\frac{7}{3}x + 10 \), we calculate the corresponding \( y \) values for each chosen \( x \).

For \( x_1 = 0 \): \[ y_1 = -\frac{7}{3} \times 0 + 10 = 10.0 \]

For \( x_2 = 3 \): \[ y_2 = -\frac{7}{3} \times 3 + 10 = 3.0 \]

Step 3: Identify the Points

The points on the graph corresponding to the chosen \( x \) values are:

  • For \( x_1 = 0 \), the point is \((0, 10.0)\).
  • For \( x_2 = 3 \), the point is \((3, 3.0)\).

Final Answer

\(\boxed{(0, 10), (3, 3)}\)

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