Questions: Find two different points on the graph of the equation (y=-frac73 x+10) ((square square square ),( square square )

Find two different points on the graph of the equation (y=-frac73 x+10) ((square square square ),( square square )
Transcript text: Find two different points on the graph of the equation $y=-\frac{7}{3} x+10$ $(\square$ $\square$ $\square$ ),( $\square$ $\square$ )
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Solution

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Solution Steps

To find two different points on the graph of the equation y=73x+10 y = -\frac{7}{3}x + 10 , we can choose two different values for x x and calculate the corresponding y y values using the equation. This will give us two points in the form (x,y)(x, y).

Step 1: Choose Values for x x

To find two points on the graph of the equation y=73x+10 y = -\frac{7}{3}x + 10 , we start by selecting two different values for x x . Let's choose x1=0 x_1 = 0 and x2=3 x_2 = 3 .

Step 2: Calculate Corresponding y y Values

Using the equation y=73x+10 y = -\frac{7}{3}x + 10 , we calculate the corresponding y y values for each chosen x x .

For x1=0 x_1 = 0 : y1=73×0+10=10.0 y_1 = -\frac{7}{3} \times 0 + 10 = 10.0

For x2=3 x_2 = 3 : y2=73×3+10=3.0 y_2 = -\frac{7}{3} \times 3 + 10 = 3.0

Step 3: Identify the Points

The points on the graph corresponding to the chosen x x values are:

  • For x1=0 x_1 = 0 , the point is (0,10.0)(0, 10.0).
  • For x2=3 x_2 = 3 , the point is (3,3.0)(3, 3.0).

Final Answer

(0,10),(3,3)\boxed{(0, 10), (3, 3)}

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