To solve the inequality \(\frac{3(x-1)}{2} \leq x-3\), we can follow these steps:
Multiply both sides of the inequality by 2 to eliminate the fraction: \[ 3(x-1) \leq 2(x-3) \]
Distribute and simplify both sides: \[ 3x - 3 \leq 2x - 6 \]
Subtract \(2x\) from both sides: \[ x - 3 \leq -6 \]
Add 3 to both sides: \[ x \leq -3 \]
The solution to the inequality is: \[ \boxed{x \leq -3} \]
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