Questions: An investment of 6000 was made 5 years ago and has grown to 7,500. What is the annual simple interest rate of this investment?
Transcript text: b) An investment of $\$ 6000$ was made 5 years ago and has grown to $\$ 7,500$. What is the annual simple interest rate of this investment?
Solution
Solution Steps
To find the annual simple interest rate, we can use the formula for simple interest:
\[ A = P(1 + rt) \]
where \( A \) is the amount of money accumulated after n years, including interest, \( P \) is the principal amount (the initial amount of money), \( r \) is the annual interest rate, and \( t \) is the time the money is invested for in years. We need to solve for \( r \).
Solution Approach
Identify the given values: \( P = 6000 \), \( A = 7500 \), and \( t = 5 \).
Rearrange the simple interest formula to solve for \( r \).
Substitute the given values into the formula and solve for \( r \).
Step 1: Identify Given Values
We are given the following values:
Principal amount \( P = 6000 \)
Amount after 5 years \( A = 7500 \)
Time period \( t = 5 \)
Step 2: Use the Simple Interest Formula
The formula for the amount accumulated with simple interest is given by:
\[
A = P(1 + rt)
\]
We need to rearrange this formula to solve for the annual interest rate \( r \):
\[
r = \frac{A}{P} - 1 \quad \text{and then} \quad r = \frac{A/P - 1}{t}
\]
Step 3: Substitute Values and Calculate
Substituting the known values into the rearranged formula:
\[
r = \frac{7500 / 6000 - 1}{5}
\]
Calculating \( \frac{7500}{6000} \):
\[
\frac{7500}{6000} = 1.25
\]
Thus,
\[
r = \frac{1.25 - 1}{5} = \frac{0.25}{5} = 0.05
\]
Step 4: Convert to Percentage
To express \( r \) as a percentage, we multiply by 100:
\[
r \times 100 = 0.05 \times 100 = 5.00\%
\]
Final Answer
The annual simple interest rate is \\(\boxed{5.00\%}\\).