Questions: The statement to get input from keyboard and put it in a variable (x) with double as its type is scanf("%d", x); scanf("%5.2lf", x); scanf("%lf",x);

The statement to get input from keyboard and put it in a variable (x) with double as its type is scanf("%d", x); scanf("%5.2lf", x); scanf("%lf",x);
Transcript text: The statement to get input from keyboard and put it in a variable $x$ with double as its type is scanf("\%d", \&x); scanf("\%5.2lf", \&x); scanf("\%lf",x);
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Solution

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The answer is the third one: scanf("\\%5.2lf", \\&x);

Explanation for each option:

  1. scanf(" \\% 1 f ", \\& x):

    • This option is incorrect. The format specifier \\% 1 f is not valid for reading a double. The correct format specifier for a double is \\%lf.
  2. scanf("\\%d", \\&x);:

    • This option is incorrect. The format specifier \\%d is used for reading integers, not doubles. Using this with a double variable would lead to incorrect behavior.
  3. scanf("\\%5.2lf", \\&x);:

    • This option is correct. The format specifier \\%lf is used for reading a double. The 5.2 part specifies the width and precision, which is valid for formatting but not necessary for reading input. However, it does not make the statement incorrect.
  4. scanf("\\%lf",x);:

    • This option is incorrect. The format specifier \\%lf is correct for a double, but the variable x is missing the address-of operator &. It should be \\&x to correctly store the input in the variable x.

In summary, the correct statement to read a double from the keyboard and store it in the variable x is scanf("\\%5.2lf", \\&x);.

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