Questions: The statement to get input from keyboard and put it in a variable (x) with double as its type is scanf("%d", x); scanf("%5.2lf", x); scanf("%lf",x);
Transcript text: The statement to get input from keyboard and put it in a variable $x$ with double as its type is
scanf("\%d", \&x);
scanf("\%5.2lf", \&x);
scanf("\%lf",x);
Solution
The answer is the third one: scanf("\\%5.2lf", \\&x);
Explanation for each option:
scanf(" \\% 1 f ", \\& x):
This option is incorrect. The format specifier \\% 1 f is not valid for reading a double. The correct format specifier for a double is \\%lf.
scanf("\\%d", \\&x);:
This option is incorrect. The format specifier \\%d is used for reading integers, not doubles. Using this with a double variable would lead to incorrect behavior.
scanf("\\%5.2lf", \\&x);:
This option is correct. The format specifier \\%lf is used for reading a double. The 5.2 part specifies the width and precision, which is valid for formatting but not necessary for reading input. However, it does not make the statement incorrect.
scanf("\\%lf",x);:
This option is incorrect. The format specifier \\%lf is correct for a double, but the variable x is missing the address-of operator &. It should be \\&x to correctly store the input in the variable x.
In summary, the correct statement to read a double from the keyboard and store it in the variable x is scanf("\\%5.2lf", \\&x);.