Questions: Question 4 Solve the system of equations by elimination. 2x - 6y = -72 9x - 7y = -144 x = y =

Question 4

Solve the system of equations by elimination.

2x - 6y = -72
9x - 7y = -144

x =
y =
Transcript text: Question 4 Solve the system of equations by elimination. \[ \begin{array}{l} 2 x-6 y=-72 \\ 9 x-7 y=-144 \end{array} \] \[ x= \] $y=$
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Solution

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Solution Steps

To solve the system of equations using elimination, we aim to eliminate one of the variables by making the coefficients of either \(x\) or \(y\) the same in both equations. We can multiply the first equation by 9 and the second equation by 2 to align the coefficients of \(x\). Then, we subtract one equation from the other to eliminate \(x\) and solve for \(y\). Once \(y\) is found, substitute it back into one of the original equations to solve for \(x\).

Step 1: Align Coefficients for Elimination

To eliminate one of the variables, we align the coefficients of \(x\) by multiplying the first equation by 9 and the second equation by 2: \[ \begin{align_} 9(2x - 6y) &= 9(-72) \\ 2(9x - 7y) &= 2(-144) \end{align_} \] This results in: \[ \begin{align_} 18x - 54y &= -648 \\ 18x - 14y &= -288 \end{align_} \]

Step 2: Eliminate \(x\)

Subtract the second equation from the first to eliminate \(x\): \[ (18x - 54y) - (18x - 14y) = -648 - (-288) \] \[ -54y + 14y = -648 + 288 \] \[ -40y = -360 \]

Step 3: Solve for \(y\)

Divide both sides by \(-40\) to solve for \(y\): \[ y = \frac{-360}{-40} = 9 \]

Step 4: Substitute \(y\) to Solve for \(x\)

Substitute \(y = 9\) back into the first original equation: \[ 2x - 6(9) = -72 \] \[ 2x - 54 = -72 \] \[ 2x = -72 + 54 \] \[ 2x = -18 \] \[ x = \frac{-18}{2} = -9 \]

Final Answer

The solution to the system of equations is: \[ \boxed{x = -9}, \quad \boxed{y = 9} \]

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