Questions: Choose the correct graph of y=4 csc(2 x-pi/6).
Transcript text: Choose the correct graph of $y=4 \csc \left(2 x-\frac{\pi}{6}\right)$.
Solution
Solution Steps
Step 1: Identify the function and its properties
The given function is \( y = 4 \csc \left( 2x - \frac{\pi}{6} \right) \). The cosecant function, \( \csc(x) \), is the reciprocal of the sine function, \( \sin(x) \). The function \( y = 4 \csc \left( 2x - \frac{\pi}{6} \right) \) will have vertical asymptotes where the sine function is zero.
Step 2: Determine the period and phase shift
The period of the cosecant function \( \csc(bx - c) \) is \( \frac{2\pi}{b} \). Here, \( b = 2 \), so the period is \( \frac{2\pi}{2} = \pi \). The phase shift is determined by solving \( 2x - \frac{\pi}{6} = 0 \), which gives \( x = \frac{\pi}{12} \).
Step 3: Identify the vertical asymptotes and key points
The vertical asymptotes occur where \( \sin \left( 2x - \frac{\pi}{6} \right) = 0 \). Solving \( 2x - \frac{\pi}{6} = n\pi \) (where \( n \) is an integer), we get \( x = \frac{\pi}{12} + \frac{n\pi}{2} \). This gives asymptotes at \( x = \frac{\pi}{12}, \frac{13\pi}{12}, \frac{25\pi}{12}, \ldots \).
Final Answer
The correct graph is C. It shows the vertical asymptotes at \( x = \frac{\pi}{12} \) and \( x = \frac{25\pi}{12} \), and the correct shape of the \( 4 \csc \left( 2x - \frac{\pi}{6} \right) \) function.