To solve the given expression, follow these steps:
Convert \(3 \frac{3}{4}\) and \(-2 \frac{3}{4}\) to improper fractions: \[ 3 \frac{3}{4} = \frac{3 \times 4 + 3}{4} = \frac{15}{4} \] \[ -2 \frac{3}{4} = \frac{-2 \times 4 - 3}{4} = \frac{-11}{4} \]
Multiply \(\frac{-11}{4}\) by \(2\): \[ \frac{-11}{4} \times 2 = \frac{-11 \times 2}{4} = \frac{-22}{4} = \frac{-11}{2} \]
Add \(\frac{15}{4}\) and \(\frac{-11}{2}\): \[ \frac{15}{4} + \frac{-11}{2} = \frac{15}{4} + \frac{-22}{4} = \frac{15 - 22}{4} = \frac{-7}{4} \]
Divide \(\frac{-7}{4}\) by \(-5\): \[ \frac{-7}{4} \div -5 = \frac{-7}{4} \times \frac{1}{-5} = \frac{-7 \times 1}{4 \times -5} = \frac{7}{20} \]
\(\boxed{\frac{7}{20}}\)
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