The characteristic chosen for analysis is calories. This data is quantitative as it represents numerical values.
To calculate the mean (\( \mu \)), we use the formula:
\[
\mu = \frac{\sum_{i=1}^N x_i}{N} = \frac{1640}{15} = 109.33
\]
Thus, the mean of calories is:
\[
\text{Mean of calories: } 109.33
\]
Next, we find the median. The sorted data is:
\[
\text{Sorted data: } [50, 80, 100, 110, 110, 110, 110, 110, 110, 110, 120, 120, 120, 120, 160]
\]
Using the formula for the rank of the median:
\[
\text{Rank} = Q \times (N + 1) = 0.5 \times (15 + 1) = 8.0
\]
The quantile is at position 8, which corresponds to the value:
\[
\text{Median of calories: } 110
\]
For the mode, since the most frequently occurring value is:
\[
\text{Mode of calories: } 110
\]
The range of calories is calculated as:
\[
\text{Range} = \max(x) - \min(x) = 160 - 50 = 110
\]
To describe the spread of the distribution, we calculate the variance (\( \sigma^2 \)) and standard deviation (\( \sigma \)):
\[
\sigma^2 = \frac{\sum (x_i - \mu)^2}{n-1} = 535.24
\]
\[
\sigma = \sqrt{535.24} = 23.14
\]
Thus, we have:
\[
\text{Variance of calories: } 535.24
\]
\[
\text{Standard Deviation of calories: } 23.14
\]
- Mean of calories: \( \mu = 109.33 \)
- Median of calories: \( 110 \)
- Mode of calories: \( 110 \)
- Range of calories: \( 110 \)
- Variance of calories: \( 535.24 \)
- Standard Deviation of calories: \( 23.14 \)
\[
\boxed{\text{Mean: } 109.33, \text{ Median: } 110, \text{ Mode: } 110, \text{ Range: } 110, \text{ Variance: } 535.24, \text{ Standard Deviation: } 23.14}
\]