Given the function $f(x) = 1 \cdot (1 \cdot x - 2)^{\frac{1}{3}} + 5$, we aim to find its inverse.
First, isolate the root expression by subtracting 5 from both sides: $y - 5 = 1 \cdot (1 \cdot x - 2)^{\frac{1}{3}}$.
Then, divide both sides by 1 to isolate the root expression: $\frac{y - 5}{1} = (1 \cdot x - 2)^{\frac{1}{3}}$.
Raise both sides to the power of 3 to eliminate the root: $\left(\frac{y - 5}{1}\right)^{3} = 1 \cdot x - 2$.
Finally, solve for x by subtracting -2 and dividing by 1: $x = \frac{\left(\frac{y - 5}{1}\right)^{3} + 2}{1}$.
$f^{-1}(x) = \frac{\left(\frac{x - 5}{1}\right)^{3} + 2}{1}$, rounded to 0 decimal places.
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