Questions: Find the standard deviation for the group of data items. 11,12,13,14,15 The standard deviation is (Round to two decimal places as needed.)

Find the standard deviation for the group of data items.
11,12,13,14,15

The standard deviation is 
(Round to two decimal places as needed.)
Transcript text: Find the standard deviation for the group of data items. \[ 11,12,13,14,15 \] The standard deviation is $\square$ (Round to two decimal places as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Mean

The mean \( \mu \) of the dataset is calculated as follows:

\[ \mu = \frac{\sum x_i}{n} = \frac{11 + 12 + 13 + 14 + 15}{5} = \frac{65}{5} = 13.0 \]

Step 2: Calculate the Variance

The variance \( \sigma^2 \) is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{n} \]

Calculating each term:

  • For \( x_1 = 11 \): \( (11 - 13)^2 = 4 \)
  • For \( x_2 = 12 \): \( (12 - 13)^2 = 1 \)
  • For \( x_3 = 13 \): \( (13 - 13)^2 = 0 \)
  • For \( x_4 = 14 \): \( (14 - 13)^2 = 1 \)
  • For \( x_5 = 15 \): \( (15 - 13)^2 = 4 \)

Now summing these values:

\[ \sum (x_i - \mu)^2 = 4 + 1 + 0 + 1 + 4 = 10 \]

Thus, the variance is:

\[ \sigma^2 = \frac{10}{5} = 2.0 \]

Step 3: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{2.0} \approx 1.41 \]

Final Answer

The variance is \( 2.0 \) and the standard deviation is \( 1.41 \).

\[ \boxed{\text{Variance} = 2.0, \text{ Standard Deviation} = 1.41} \]

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