The problem provides the lengths of two sides of the triangle and the included angle:
The formula to find the area \( A \) of a triangle when two sides and the included angle are known is: \[ A = \frac{1}{2}ab \sin(C) \]
Substitute \( a = 9 \) ft, \( b = 20 \) ft, and \( C = 110^\circ \) into the formula: \[ A = \frac{1}{2} \times 9 \times 20 \times \sin(110^\circ) \]
Using a calculator, find \( \sin(110^\circ) \): \[ \sin(110^\circ) \approx 0.9397 \]
Calculate the area: \[ A = \frac{1}{2} \times 9 \times 20 \times 0.9397 \] \[ A = \frac{1}{2} \times 180 \times 0.9397 \] \[ A = 90 \times 0.9397 \] \[ A \approx 84.573 \]
Round the result to the nearest tenth: \[ A \approx 84.6 \]
The area of the triangle is approximately \( 84.6 \) square feet.
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